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數學一問........................................

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發問:

我數學有唔識 6(x-y)^2-z(y-x)+5x-5y 2(5x-3)^2-9(5x-3)+10 十萬火急..請連同計算步驟一同列出

最佳解答:

6(x-y)^2-z(y-x)+5x-5y =6(x-y)^2-z(y-x)+5(x-y) =6(x-y)^2-zy+zx+5(x-y) =6(x-y)^2+z(x-y)+5(x-y) =(x-y)(6(x-y)+z+5) =(x-y)(6x-6y+z+5) 2(5x-3)^2-9(5x-3)+10 =(5x-3)(2(5x-3)-9)+10 =(5x-3)(10x-15)+10 =50x^2-105x+55 =(50x+55)(-x-1)

其他解答:

6(x-y)^2-z(y-x)+5x-5y =6(x-y)^2-z(y-x)+5(x-y) =6(x-y)^2-zy+zx+5(x-y) =6(x-y)^2+z(x-y)+5(x-y) =(x-y)(6(x-y)+z+5) =(x-y)(6x-6y+z+5) 2(5x-3)^2-9(5x-3)+10 =(5x-3)(2(5x-3)-9)+10 =(5x-3)(10x-15)+10 =50x^2-105x+55 =(50x+55)(-x-1)
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