close
標題:
Maths Question
發問:
最佳解答:
(x-y)(y-z)(z-x) = xyz - x^2 - y^2 - z^2 ___________________________ LHS: (x-y)(y-z)(z-x) (x(y-z)-y(y-z))(z-x) z(xy-xz-y^2+yz)-x(xy-xz-y^2+yz) xyz-xz^2-zy^2+yz^2-x^2y+x^2z+xy^2-xyz-zy^2+yz^2-x^2y+xy^2 ___________________ RHS xyz - x^2 - y^2 - z^2 It is not an identity!
其他解答:
Maths Question
發問:
此文章來自奇摩知識+如有不便請留言告知
(x-y)(y-z)(z-x) = xyz - x^2 - y^2 - z^2Determine whether each of the following equations is an identityfull step... 顯示更多 (x-y)(y-z)(z-x) = xyz - x^2 - y^2 - z^2 Determine whether each of the following equations is an identity full step plz +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++最佳解答:
(x-y)(y-z)(z-x) = xyz - x^2 - y^2 - z^2 ___________________________ LHS: (x-y)(y-z)(z-x) (x(y-z)-y(y-z))(z-x) z(xy-xz-y^2+yz)-x(xy-xz-y^2+yz) xyz-xz^2-zy^2+yz^2-x^2y+x^2z+xy^2-xyz-zy^2+yz^2-x^2y+xy^2 ___________________ RHS xyz - x^2 - y^2 - z^2 It is not an identity!
其他解答:
文章標籤
全站熱搜
留言列表
