標題:
How to solve 2x(1+x二次)
How to solve 2x(1+x二次) THX
最佳解答:
let y = 2x(1+x^2) = 0 then, 2x =0 or 1+x^2 =0 x = 0 or x^2 = -1 for x^2 = -1, x = (-1)^(1/2) ... there is NO real root since i = (-1)^(1/2) in complex number therefore the ans are x = 0 and x = i
其他解答:
2x(1+x^2) =2x+2x^3|||||2x( 1+ x^2) = 2x + 2x^3
How to solve 2x(1+x二次)
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發問:How to solve 2x(1+x二次) THX
最佳解答:
let y = 2x(1+x^2) = 0 then, 2x =0 or 1+x^2 =0 x = 0 or x^2 = -1 for x^2 = -1, x = (-1)^(1/2) ... there is NO real root since i = (-1)^(1/2) in complex number therefore the ans are x = 0 and x = i
其他解答:
2x(1+x^2) =2x+2x^3|||||2x( 1+ x^2) = 2x + 2x^3
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