A physic question－香港介紹ppt

標題:

A physic question

發問:

Iron blocks, A and B, are heated by heaters C and D respectively for the same period of time. The ratio of the power of to that of D is 3:4. If the ratio of the temperature change of A to that of B is 4:3, what is the ratio of the mass of A to that of B? STEPS PLS. 最好有中英答案

最佳解答:

Iron blocks, A and B, are heated by heaters C and D respectively for the same period of time. The ratio of the power of to that of D is 3:4. If the ratio of the temperature change of A to that of B is 4:3, what is the ratio of the mass of A to that of B? E=mcΔT E=Pt We have P(C)t=m(A)c(A)ΔT(A)...(1) P(D)t=m(B)c(B)ΔT(B) That is (4/3)P(C)t=m(B)c(A)(3/4)ΔT(A) (16/9)P(C)t=m(B)c(A)(3/4)ΔT(A)...(2) (2)/(1): So 16/9=m(B)/m(A) or m(A)/m(B)=9/16 The ratio of the mass of A to that of B is 9/16

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